| Write an equation for the parabola whose vertex is at (-1, 4) and passes through (2, 1). |
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Step 1 |
The
vertex of the parabola is at (-1, 4) so h = -1 and k = 4. Since (2, 1) is a point on the graph of the parabola, let x = 2 and y = 1. Substitute these values into the vertex form of the equation and solve for a. |
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y = a(x - h)^2 + k \quad \quad Vertex
Form. 1 = a[2 - (-1)]^2 + 4 \quad \quad \quad Substitute 1 for y, 2 for x, -1 for h, and 4 for k. |
Step 2 |
Simplify
the expression . |
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1 = a(9) + 4 |
Step 3 |
Subtract
4 from each side . |
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-3 = 9a |
Step 4 |
Divide
each side by 9 . |
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-\frac{1}{3} = a |
Step 5 |
Write
the equation in vertex form. |
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y = -\frac{1}{3}(x + 1)^2 + 4 |
Step 6 |
Check. A graph of \quad y = -\frac{1}{3}(x + 1)^2 + 4 \quad verifies that the parabola passes through the point (2, 1). |
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